# Correction to "New issues and results in nonlinear systems stability"

• Itzhak Barkana BARKANA Consulting, 11/3 Hashomer St., Ramat Hasharon 4720937, Israel. Phone: +972-3-5405973.

### Abstract

In paper "New issues and results in nonlinear systems stability" by Itzhak Barkana, which appeared in MESA (MATHEMATICS IN ENGINEERING, SCIENCE AND AEROSPACE), Vol. 11, No. 3, pp. 671-684, 2020, a typo fell that might confuse the reader.

At the end of section 5.2, maybe under the influence of the previous example of section 5.1, an erroneous division by t appears. Therefore, instead of

$\dot{f}_k(t)=\frac{df_k(t)}{dt}=\mathop {\lim }\limits_{h \to 0 }(\mathop {\lim }\limits_{t \to \infty }{(\frac{f_k(t+h)-f_k(t)}{h}))} =\mathop {\lim }\limits_{h \to 0 }(\mathop {\lim }\limits_{t \to \infty }{(\frac{\frac{sin((t+h)e^{-(t+h)^{2k}sin^2(t+h)})}{t+h}-\frac{sin(t)e^{-t^{2k}sin^2(t)}}{t}}{h})})$

should be

$\dot{f}_k(t)=\frac{df_k(t)}{dt}=\mathop {\lim }\limits_{h \to 0 }(\mathop {\lim }\limits_{t \to \infty }{(\frac{f_k(t+h)-f_k(t)}{h}))} =\mathop {\lim }\limits_{h \to 0 }(\mathop {\lim }\limits_{t \to \infty }{(\frac{sin(t+h)e^{-(t+h)^{2k}sin^2(t+h)}-sin(t)e^{-t^{2k}sin^2(t)}}{h}}))$

All the rest remain the same.

Published
2021-11-26
Section
Articles